C program to print a string character by character using pointer

In this C program, we are going to learn how to read and print (character by character) a string using pointer?
Here, we have two variables, str is a string variable and ptr is a character pointer, that will point to the string variable str.
First of all, we are reading string in str and then assigning the base address of str to the character pointer ptr by using ptr=str or it can also be done by using ptr = &str[0].
And, finally we are printing the string character by character until NULL not found. Characters are printing by the pointer *ptr.
Consider the program
/*C program to print a string using pointer.*/
#include <stdio.h>
int main()
{
    char str[100];
    char *ptr;
     
    printf("Enter a string: ");
    gets(str);
     
    //assign address of str to ptr
    ptr=str;
     
    printf("Entered string is: ");
    while(*ptr!='\0')
        printf("%c",*ptr++);
         
    return 0;
}

Advertisements

Output
Enter a string: This is a test string.
Entered string is: This is a test string.

Comments

Post a Comment

Popular posts from this blog

C Program to Check Whether a Character is an Alphabet or not

In this example, you will learn to check whether a character entered by the user is an alphabet or not. To understand this example, you should have the knowledge of following C programming topics: C Programming Operators C if, if...else and Nested if...else Statement Example: Program to Check Alphabet #include <stdio.h> int main () { char c ; printf ( "Enter a character: " ); scanf ( "%c" ,& c ); if ( ( c >= 'a' && c <= 'z' ) || ( c >= 'A' && c <= 'Z' )) printf ( "%c is an alphabet." , c ); else printf ( "%c is not an alphabet." , c ); return 0 ; } Output Enter a character: * * is not an alphabet In C programming, a character variable holds ASCII value (an integer number between 0 and 127) rather than that character itself. The ASCII value of lowercase alphabets are from
Read more

C Program to Calculate the Sum of Natural Numbers

To compute the sum of natural numbers from 1 to n (entered by the user), loops can be used. You will learn how to use for loop and while loop to solve this problem. To understand this example, you should have the knowledge of following C programming topics: C Programming for Loop C Programming while and do...while Loop The positive numbers 1, 2, 3... are known as natural numbers. The programs below takes a positive integer (let say  n ) as an input from the user and calculates the sum up to  n . Example #1: Sum of Natural Numbers Using for Loop #include <stdio.h> int main () { int n , i , sum = 0 ; printf ( "Enter a positive integer: " ); scanf ( "%d" ,& n ); for ( i = 1 ; i <= n ; ++ i ) { sum += i ; // sum = sum+i; } printf ( "Sum = %d" , sum ); return 0 ; } The above program takes the input from the user and stores in variabl
Read more

C Program to Count Number of Digits in an Integer

Example to count the number of digits in an integer entered by the user. The while loop is used to solve this program. To understand this example, you should have the knowledge of following C programming topics: C Programming Operators C Programming while and do...while Loop This program takes an integer from the user and calculates the number of digits. For example: If the user enters 2319, the output of the program will be 4. Read -  Programming language Example #1: Program to Count Number of Digits in an Integer #include <stdio.h> int main () { long long n ; int count = 0 ; printf ( "Enter an integer: " ); scanf ( "%lld" , & n ); while ( n != 0 ) { // n = n/10 n /= 10 ; ++ count ; } printf ( "Number of digits: %d" , count ); } Output Enter an integer: 3452 Number of digits: 4 The integer entered by the user is stored
Read more